Kyrgyz wrestler Tynybekova to compete in Women's World Cup with Romanian athlete

Bishkek, Dec. 14 / Kabar /. The rival of the athlete Aisuluu Tynybekova in the Women's World Cup was determined. According to the website of the United Wrestling World, the competitions are held in Belgrade (Serbia) from 12 to 18 December. Tynybekova will fight in the weight category 62 kg with the Romanian athlete Christa Tunde Inkze. Kyrgyzstani athletes Aiperi Medet kyzy (76 kg), Meerim Zhumanazarova (68 kg), Nuraida Anarkulova (57 kg) also take part in the World Cup.